Integrand size = 27, antiderivative size = 287 \[ \int \frac {x \left (d+e x^2\right )}{\sqrt {a x+b x^3+c x^5}} \, dx=\frac {2 d x^2 \sqrt {1+\frac {2 c x^2}{b-\sqrt {b^2-4 a c}}} \sqrt {1+\frac {2 c x^2}{b+\sqrt {b^2-4 a c}}} \operatorname {AppellF1}\left (\frac {3}{4},\frac {1}{2},\frac {1}{2},\frac {7}{4},-\frac {2 c x^2}{b-\sqrt {b^2-4 a c}},-\frac {2 c x^2}{b+\sqrt {b^2-4 a c}}\right )}{3 \sqrt {a x+b x^3+c x^5}}+\frac {2 e x^4 \sqrt {1+\frac {2 c x^2}{b-\sqrt {b^2-4 a c}}} \sqrt {1+\frac {2 c x^2}{b+\sqrt {b^2-4 a c}}} \operatorname {AppellF1}\left (\frac {7}{4},\frac {1}{2},\frac {1}{2},\frac {11}{4},-\frac {2 c x^2}{b-\sqrt {b^2-4 a c}},-\frac {2 c x^2}{b+\sqrt {b^2-4 a c}}\right )}{7 \sqrt {a x+b x^3+c x^5}} \]
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Time = 0.25 (sec) , antiderivative size = 287, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.148, Rules used = {1968, 1349, 1155, 524} \[ \int \frac {x \left (d+e x^2\right )}{\sqrt {a x+b x^3+c x^5}} \, dx=\frac {2 d x^2 \sqrt {\frac {2 c x^2}{b-\sqrt {b^2-4 a c}}+1} \sqrt {\frac {2 c x^2}{\sqrt {b^2-4 a c}+b}+1} \operatorname {AppellF1}\left (\frac {3}{4},\frac {1}{2},\frac {1}{2},\frac {7}{4},-\frac {2 c x^2}{b-\sqrt {b^2-4 a c}},-\frac {2 c x^2}{b+\sqrt {b^2-4 a c}}\right )}{3 \sqrt {a x+b x^3+c x^5}}+\frac {2 e x^4 \sqrt {\frac {2 c x^2}{b-\sqrt {b^2-4 a c}}+1} \sqrt {\frac {2 c x^2}{\sqrt {b^2-4 a c}+b}+1} \operatorname {AppellF1}\left (\frac {7}{4},\frac {1}{2},\frac {1}{2},\frac {11}{4},-\frac {2 c x^2}{b-\sqrt {b^2-4 a c}},-\frac {2 c x^2}{b+\sqrt {b^2-4 a c}}\right )}{7 \sqrt {a x+b x^3+c x^5}} \]
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Rule 524
Rule 1155
Rule 1349
Rule 1968
Rubi steps \begin{align*} \text {integral}& = \frac {\left (\sqrt {x} \sqrt {a+b x^2+c x^4}\right ) \int \frac {\sqrt {x} \left (d+e x^2\right )}{\sqrt {a+b x^2+c x^4}} \, dx}{\sqrt {a x+b x^3+c x^5}} \\ & = \frac {\left (\sqrt {x} \sqrt {a+b x^2+c x^4}\right ) \int \left (\frac {d \sqrt {x}}{\sqrt {a+b x^2+c x^4}}+\frac {e x^{5/2}}{\sqrt {a+b x^2+c x^4}}\right ) \, dx}{\sqrt {a x+b x^3+c x^5}} \\ & = \frac {\left (d \sqrt {x} \sqrt {a+b x^2+c x^4}\right ) \int \frac {\sqrt {x}}{\sqrt {a+b x^2+c x^4}} \, dx}{\sqrt {a x+b x^3+c x^5}}+\frac {\left (e \sqrt {x} \sqrt {a+b x^2+c x^4}\right ) \int \frac {x^{5/2}}{\sqrt {a+b x^2+c x^4}} \, dx}{\sqrt {a x+b x^3+c x^5}} \\ & = \frac {\left (d \sqrt {x} \sqrt {1+\frac {2 c x^2}{b-\sqrt {b^2-4 a c}}} \sqrt {1+\frac {2 c x^2}{b+\sqrt {b^2-4 a c}}}\right ) \int \frac {\sqrt {x}}{\sqrt {1+\frac {2 c x^2}{b-\sqrt {b^2-4 a c}}} \sqrt {1+\frac {2 c x^2}{b+\sqrt {b^2-4 a c}}}} \, dx}{\sqrt {a x+b x^3+c x^5}}+\frac {\left (e \sqrt {x} \sqrt {1+\frac {2 c x^2}{b-\sqrt {b^2-4 a c}}} \sqrt {1+\frac {2 c x^2}{b+\sqrt {b^2-4 a c}}}\right ) \int \frac {x^{5/2}}{\sqrt {1+\frac {2 c x^2}{b-\sqrt {b^2-4 a c}}} \sqrt {1+\frac {2 c x^2}{b+\sqrt {b^2-4 a c}}}} \, dx}{\sqrt {a x+b x^3+c x^5}} \\ & = \frac {2 d x^2 \sqrt {1+\frac {2 c x^2}{b-\sqrt {b^2-4 a c}}} \sqrt {1+\frac {2 c x^2}{b+\sqrt {b^2-4 a c}}} F_1\left (\frac {3}{4};\frac {1}{2},\frac {1}{2};\frac {7}{4};-\frac {2 c x^2}{b-\sqrt {b^2-4 a c}},-\frac {2 c x^2}{b+\sqrt {b^2-4 a c}}\right )}{3 \sqrt {a x+b x^3+c x^5}}+\frac {2 e x^4 \sqrt {1+\frac {2 c x^2}{b-\sqrt {b^2-4 a c}}} \sqrt {1+\frac {2 c x^2}{b+\sqrt {b^2-4 a c}}} F_1\left (\frac {7}{4};\frac {1}{2},\frac {1}{2};\frac {11}{4};-\frac {2 c x^2}{b-\sqrt {b^2-4 a c}},-\frac {2 c x^2}{b+\sqrt {b^2-4 a c}}\right )}{7 \sqrt {a x+b x^3+c x^5}} \\ \end{align*}
Time = 11.18 (sec) , antiderivative size = 239, normalized size of antiderivative = 0.83 \[ \int \frac {x \left (d+e x^2\right )}{\sqrt {a x+b x^3+c x^5}} \, dx=\frac {2 \sqrt {\frac {b-\sqrt {b^2-4 a c}+2 c x^2}{b-\sqrt {b^2-4 a c}}} \sqrt {\frac {b+\sqrt {b^2-4 a c}+2 c x^2}{b+\sqrt {b^2-4 a c}}} \left (7 d x^2 \operatorname {AppellF1}\left (\frac {3}{4},\frac {1}{2},\frac {1}{2},\frac {7}{4},-\frac {2 c x^2}{b+\sqrt {b^2-4 a c}},\frac {2 c x^2}{-b+\sqrt {b^2-4 a c}}\right )+3 e x^4 \operatorname {AppellF1}\left (\frac {7}{4},\frac {1}{2},\frac {1}{2},\frac {11}{4},-\frac {2 c x^2}{b+\sqrt {b^2-4 a c}},\frac {2 c x^2}{-b+\sqrt {b^2-4 a c}}\right )\right )}{21 \sqrt {x \left (a+b x^2+c x^4\right )}} \]
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\[\int \frac {x \left (e \,x^{2}+d \right )}{\sqrt {c \,x^{5}+b \,x^{3}+a x}}d x\]
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\[ \int \frac {x \left (d+e x^2\right )}{\sqrt {a x+b x^3+c x^5}} \, dx=\int { \frac {{\left (e x^{2} + d\right )} x}{\sqrt {c x^{5} + b x^{3} + a x}} \,d x } \]
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\[ \int \frac {x \left (d+e x^2\right )}{\sqrt {a x+b x^3+c x^5}} \, dx=\int \frac {x \left (d + e x^{2}\right )}{\sqrt {x \left (a + b x^{2} + c x^{4}\right )}}\, dx \]
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\[ \int \frac {x \left (d+e x^2\right )}{\sqrt {a x+b x^3+c x^5}} \, dx=\int { \frac {{\left (e x^{2} + d\right )} x}{\sqrt {c x^{5} + b x^{3} + a x}} \,d x } \]
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\[ \int \frac {x \left (d+e x^2\right )}{\sqrt {a x+b x^3+c x^5}} \, dx=\int { \frac {{\left (e x^{2} + d\right )} x}{\sqrt {c x^{5} + b x^{3} + a x}} \,d x } \]
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Timed out. \[ \int \frac {x \left (d+e x^2\right )}{\sqrt {a x+b x^3+c x^5}} \, dx=\int \frac {x\,\left (e\,x^2+d\right )}{\sqrt {c\,x^5+b\,x^3+a\,x}} \,d x \]
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